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27949733113 = 107261212459
BaseRepresentation
bin11010000001111011…
…110001010011111001
32200010212100112221111
4122001323301103321
5424220112424423
620501231440321
72006422545241
oct320173612371
980125315844
1027949733113
1110942994195
1255003860a1
13283569b023
1414d2026b21
15ad8b3760d
hex681ef14f9

27949733113 has 4 divisors (see below), whose sum is σ = 28210945680. Its totient is φ = 27688520548.

The previous prime is 27949733069. The next prime is 27949733171. The reversal of 27949733113 is 31133794972.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 27949733113 - 217 = 27949602041 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (27949733173) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 130606123 + ... + 130606336.

It is an arithmetic number, because the mean of its divisors is an integer number (7052736420).

Almost surely, 227949733113 is an apocalyptic number.

It is an amenable number.

27949733113 is a deficient number, since it is larger than the sum of its proper divisors (261212567).

27949733113 is a wasteful number, since it uses less digits than its factorization.

27949733113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 261212566.

The product of its digits is 857304, while the sum is 49.

The spelling of 27949733113 in words is "twenty-seven billion, nine hundred forty-nine million, seven hundred thirty-three thousand, one hundred thirteen".

Divisors: 1 107 261212459 27949733113