Base | Representation |
---|---|
bin | 1100111001100010110110… |
… | …01111111010011111110011 |
3 | 10201102201022010000122211111 |
4 | 12130301123033322133303 |
5 | 12204220013144434303 |
6 | 140154532314454151 |
7 | 5655224256430606 |
oct | 634613317723763 |
9 | 121381263018744 |
10 | 28365494921203 |
11 | 904681443a220 |
12 | 322150aa34357 |
13 | 12a9b159b9a2b |
14 | 700c7c1c633d |
15 | 342cb9327b6d |
hex | 19cc5b3fa7f3 |
28365494921203 has 16 divisors (see below), whose sum is σ = 31150928261376. Its totient is φ = 25615093609440.
The previous prime is 28365494921177. The next prime is 28365494921303. The reversal of 28365494921203 is 30212949456382.
It is a cyclic number.
It is not a de Polignac number, because 28365494921203 - 217 = 28365494790131 is a prime.
It is not an unprimeable number, because it can be changed into a prime (28365494921003) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (29) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 13344351 + ... + 15323272.
It is an arithmetic number, because the mean of its divisors is an integer number (1946933016336).
Almost surely, 228365494921203 is an apocalyptic number.
28365494921203 is a deficient number, since it is larger than the sum of its proper divisors (2785433340173).
28365494921203 is a wasteful number, since it uses less digits than its factorization.
28365494921203 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 28668234.
The product of its (nonzero) digits is 22394880, while the sum is 58.
The spelling of 28365494921203 in words is "twenty-eight trillion, three hundred sixty-five billion, four hundred ninety-four million, nine hundred twenty-one thousand, two hundred three".
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