Base | Representation |
---|---|
bin | 101010011001010011111… |
… | …011110000010100010001 |
3 | 101022111222120120020120012 |
4 | 222121103323300110101 |
5 | 340213113334000032 |
6 | 10110221243124305 |
7 | 420325445255156 |
oct | 52312373602421 |
9 | 11274876506505 |
10 | 2913396000017 |
11 | a236230a9778 |
12 | 3b0776513695 |
13 | 181969462bb9 |
14 | a101b04422d |
15 | 50bb65ce6b2 |
hex | 2a653ef0511 |
2913396000017 has 4 divisors (see below), whose sum is σ = 2916396408816. Its totient is φ = 2910395591220.
The previous prime is 2913395999977. The next prime is 2913396000043. The reversal of 2913396000017 is 7100006933192.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 2913396000017 - 228 = 2913127564561 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (2913396000617) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1500202943 + ... + 1500204884.
It is an arithmetic number, because the mean of its divisors is an integer number (729099102204).
Almost surely, 22913396000017 is an apocalyptic number.
It is an amenable number.
2913396000017 is a deficient number, since it is larger than the sum of its proper divisors (3000408799).
2913396000017 is an equidigital number, since it uses as much as digits as its factorization.
2913396000017 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 3000408798.
The product of its (nonzero) digits is 61236, while the sum is 41.
The spelling of 2913396000017 in words is "two trillion, nine hundred thirteen billion, three hundred ninety-six million, seventeen", and thus it is an aban number.
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