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29169625057 = 31940955647
BaseRepresentation
bin11011001010101001…
…010010011111100001
32210021212210111002121
4123022221102133201
5434214411000212
621222250144241
72051564502436
oct331251223741
983255714077
1029169625057
1111409547051
1257a0a22081
13299b338691
1415aa053b8d
15b5aca1d07
hex6caa527e1

29169625057 has 4 divisors (see below), whose sum is σ = 30110580736. Its totient is φ = 28228669380.

The previous prime is 29169625033. The next prime is 29169625061. The reversal of 29169625057 is 75052696192.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 29169625057 - 223 = 29161236449 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 29169624995 and 29169625013.

It is not an unprimeable number, because it can be changed into a prime (29169623057) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 470477793 + ... + 470477854.

It is an arithmetic number, because the mean of its divisors is an integer number (7527645184).

Almost surely, 229169625057 is an apocalyptic number.

It is an amenable number.

29169625057 is a deficient number, since it is larger than the sum of its proper divisors (940955679).

29169625057 is an equidigital number, since it uses as much as digits as its factorization.

29169625057 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 940955678.

The product of its (nonzero) digits is 2041200, while the sum is 52.

The spelling of 29169625057 in words is "twenty-nine billion, one hundred sixty-nine million, six hundred twenty-five thousand, fifty-seven".

Divisors: 1 31 940955647 29169625057