Base | Representation |
---|---|
bin | 1101101001000111110000… |
… | …01010111100001000001001 |
3 | 10221012222210120122200121102 |
4 | 12310203320022330020021 |
5 | 12413010420043300203 |
6 | 143445524131551145 |
7 | 6214305204563105 |
oct | 664437012741011 |
9 | 127188716580542 |
10 | 30000215212553 |
11 | 9617024424473 |
12 | 34462ab45b4b5 |
13 | 1398014bc1861 |
14 | 75a037bac905 |
15 | 370593b3a888 |
hex | 1b48f82bc209 |
30000215212553 has 4 divisors (see below), whose sum is σ = 30000667968768. Its totient is φ = 29999762456340.
The previous prime is 30000215212531. The next prime is 30000215212577. The reversal of 30000215212553 is 35521251200003.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 30000215212553 - 214 = 30000215196169 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (30000215212153) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 226278701 + ... + 226411242.
It is an arithmetic number, because the mean of its divisors is an integer number (7500166992192).
Almost surely, 230000215212553 is an apocalyptic number.
It is an amenable number.
30000215212553 is a deficient number, since it is larger than the sum of its proper divisors (452756215).
30000215212553 is an equidigital number, since it uses as much as digits as its factorization.
30000215212553 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 452756214.
The product of its (nonzero) digits is 9000, while the sum is 29.
Adding to 30000215212553 its reverse (35521251200003), we get a palindrome (65521466412556).
The spelling of 30000215212553 in words is "thirty trillion, two hundred fifteen million, two hundred twelve thousand, five hundred fifty-three".
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