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3000040400003 = 5419883561101
BaseRepresentation
bin101011101010000000010…
…101111010010010000011
3101121210121222021210211112
4223222000111322102003
5343123040320300003
610214111033233535
7426513540436253
oct53520025722203
911553558253745
103000040400003
11a5734565a909
124055175628ab
13189b9700682a
14a52ba411963
15530880743d8
hex2ba8057a483

3000040400003 has 8 divisors (see below), whose sum is σ = 3005895235056. Its totient is φ = 2994186708000.

The previous prime is 3000040399987. The next prime is 3000040400009.

3000040400003 is nontrivially palindromic in base 10.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 3000040400003 - 24 = 3000040399987 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (3000040400009) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 5066153 + ... + 5627253.

It is an arithmetic number, because the mean of its divisors is an integer number (375736904382).

Almost surely, 23000040400003 is an apocalyptic number.

3000040400003 is a deficient number, since it is larger than the sum of its proper divisors (5854835053).

3000040400003 is an equidigital number, since it uses as much as digits as its factorization.

3000040400003 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 571525.

The product of its (nonzero) digits is 144, while the sum is 14.

It can be divided in two parts, 3000040 and 400003, that added together give a palindrome (3400043).

The spelling of 3000040400003 in words is "three trillion, forty million, four hundred thousand, three".

Divisors: 1 541 9883 561101 5346703 303555641 5545361183 3000040400003