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3000102103113 = 322512621169501
BaseRepresentation
bin101011101010000100000…
…001010010100001001001
3101121210210021101122120220
4223222010001102201021
5343123202114244423
610214121115540253
7426515220055563
oct53520401224111
911553707348526
103000102103113
11a57377474315
1240553415a689
13189ba6a2ba4b
14a52c46b4333
155308d6b19e3
hex2ba84052849

3000102103113 has 16 divisors (see below), whose sum is σ = 4003463669952. Its totient is φ = 1998405000000.

The previous prime is 3000102103109. The next prime is 3000102103123. The reversal of 3000102103113 is 3113012010003.

It is not a de Polignac number, because 3000102103113 - 22 = 3000102103109 is a prime.

It is a super-2 number, since 2×30001021031132 (a number of 26 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 3000102103092 and 3000102103101.

It is not an unprimeable number, because it can be changed into a prime (3000102103123) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 17614863 + ... + 17784363.

It is an arithmetic number, because the mean of its divisors is an integer number (250216479372).

Almost surely, 23000102103113 is an apocalyptic number.

It is an amenable number.

3000102103113 is a deficient number, since it is larger than the sum of its proper divisors (1003361566839).

3000102103113 is a wasteful number, since it uses less digits than its factorization.

3000102103113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 174376.

The product of its (nonzero) digits is 54, while the sum is 15.

Adding to 3000102103113 its reverse (3113012010003), we get a palindrome (6113114113116).

The spelling of 3000102103113 in words is "three trillion, one hundred two million, one hundred three thousand, one hundred thirteen".

Divisors: 1 3 2251 2621 6753 7863 169501 508503 5899871 17699613 381546751 444262121 1144640253 1332786363 1000034034371 3000102103113