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3000130021113 = 31636135235217
BaseRepresentation
bin101011101010000101101…
…011110010011011111001
3101121210212012221000212220
4223222011223302123321
5343123231241133423
610214123554154253
7426516006263301
oct53520553623371
911553765830786
103000130021113
11a57391202545
12405541582989
13189bac755184
14a52c82a0601
1553090d789e3
hex2ba85af26f9

3000130021113 has 8 divisors (see below), whose sum is σ = 4024714303008. Its totient is φ = 1987816209984.

The previous prime is 3000130021093. The next prime is 3000130021157. The reversal of 3000130021113 is 3111200310003.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 3000130021113 - 228 = 2999861585657 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 3000130021092 and 3000130021101.

It is not an unprimeable number, because it can be changed into a prime (3000130021013) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 3067617120 + ... + 3067618097.

It is an arithmetic number, because the mean of its divisors is an integer number (503089287876).

Almost surely, 23000130021113 is an apocalyptic number.

It is an amenable number.

3000130021113 is a deficient number, since it is larger than the sum of its proper divisors (1024584281895).

3000130021113 is a wasteful number, since it uses less digits than its factorization.

3000130021113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 6135235383.

The product of its (nonzero) digits is 54, while the sum is 15.

Adding to 3000130021113 its reverse (3111200310003), we get a palindrome (6111330331116).

The spelling of 3000130021113 in words is "three trillion, one hundred thirty million, twenty-one thousand, one hundred thirteen".

Divisors: 1 3 163 489 6135235217 18405705651 1000043340371 3000130021113