Base | Representation |
---|---|
bin | 100010000110111000100000… |
… | …0000110111100000101101011 |
3 | 1110100020222022221110122112001 |
4 | 1010031301000012330011223 |
5 | 303310403343031333003 |
6 | 2542024044005431431 |
7 | 120123143032244506 |
oct | 10415610006740553 |
9 | 1410228287418461 |
10 | 300013131121003 |
11 | 87658944212043 |
12 | 2979467a70b577 |
13 | cb531699c55c1 |
14 | 54129da77413d |
15 | 24a406b56161d |
hex | 110dc401bc16b |
300013131121003 has 4 divisors (see below), whose sum is σ = 300339587194960. Its totient is φ = 299686675047048.
The previous prime is 300013131120977. The next prime is 300013131121009. The reversal of 300013131121003 is 300121131310003.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 300013131121003 - 213 = 300013131112811 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (300013131121009) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 163228035600 + ... + 163228037437.
It is an arithmetic number, because the mean of its divisors is an integer number (75084896798740).
Almost surely, 2300013131121003 is an apocalyptic number.
300013131121003 is a deficient number, since it is larger than the sum of its proper divisors (326456073957).
300013131121003 is an equidigital number, since it uses as much as digits as its factorization.
300013131121003 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 326456073956.
The product of its (nonzero) digits is 162, while the sum is 19.
Adding to 300013131121003 its reverse (300121131310003), we get a palindrome (600134262431006).
The spelling of 300013131121003 in words is "three hundred trillion, thirteen billion, one hundred thirty-one million, one hundred twenty-one thousand, three".
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