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30004441113 = 310001480371
BaseRepresentation
bin11011111100011001…
…110111000000011001
32212110001122112102210
4123330121313000121
5442422114103423
621441151145333
72111352353463
oct337431670031
985401575383
1030004441113
11117a77a7779
125994515249
132aa228b68a
141648c83133
15ba9204b93
hex6fc677019

30004441113 has 4 divisors (see below), whose sum is σ = 40005921488. Its totient is φ = 20002960740.

The previous prime is 30004441111. The next prime is 30004441121. The reversal of 30004441113 is 31114440003.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is not a de Polignac number, because 30004441113 - 21 = 30004441111 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 30004441113.

It is not an unprimeable number, because it can be changed into a prime (30004441111) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5000740183 + ... + 5000740188.

It is an arithmetic number, because the mean of its divisors is an integer number (10001480372).

Almost surely, 230004441113 is an apocalyptic number.

It is an amenable number.

30004441113 is a deficient number, since it is larger than the sum of its proper divisors (10001480375).

30004441113 is a wasteful number, since it uses less digits than its factorization.

30004441113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 10001480374.

The product of its (nonzero) digits is 576, while the sum is 21.

Adding to 30004441113 its reverse (31114440003), we get a palindrome (61118881116).

The spelling of 30004441113 in words is "thirty billion, four million, four hundred forty-one thousand, one hundred thirteen".

Divisors: 1 3 10001480371 30004441113