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301010133113 = 7314983275207
BaseRepresentation
bin1000110000101011001…
…10100010000001111001
31001202221220200002212122
410120111212202001321
514412432043224423
6350140535451025
730514211626004
oct4302546420171
91052856602778
10301010133113
11106726411258
124a407826a75
13225011a6101
14107d736a53b
157c6b1e28c8
hex46159a2079

301010133113 has 8 divisors (see below), whose sum is σ = 305155033728. Its totient is φ = 296865813024.

The previous prime is 301010133101. The next prime is 301010133163. The reversal of 301010133113 is 311331010103.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 301010133113 - 26 = 301010133049 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 301010133091 and 301010133100.

It is not an unprimeable number, because it can be changed into a prime (301010133163) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 956156 + ... + 1231362.

It is an arithmetic number, because the mean of its divisors is an integer number (38144379216).

Almost surely, 2301010133113 is an apocalyptic number.

It is an amenable number.

301010133113 is a deficient number, since it is larger than the sum of its proper divisors (4144900615).

301010133113 is a wasteful number, since it uses less digits than its factorization.

301010133113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 290263.

The product of its (nonzero) digits is 81, while the sum is 17.

Adding to 301010133113 its reverse (311331010103), we get a palindrome (612341143216).

The spelling of 301010133113 in words is "three hundred one billion, ten million, one hundred thirty-three thousand, one hundred thirteen".

Divisors: 1 73 14983 275207 1093759 20090111 4123426481 301010133113