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30101113426555 = 56020222685311
BaseRepresentation
bin1101101100000011101100…
…01011000101001001111011
310221120122020100110000211101
412312001312023011021323
512421134040014122210
6144004132142512231
76224506436341243
oct666016613051173
9127518210400741
1030101113426555
1196558a0881a96
123461969b95677
1313a46a4820a72
14760c8a242b23
15372eebb4ca3a
hex1b60762c527b

30101113426555 has 4 divisors (see below), whose sum is σ = 36121336111872. Its totient is φ = 24080890741240.

The previous prime is 30101113426543. The next prime is 30101113426577. The reversal of 30101113426555 is 55562431110103.

It is a semiprime because it is the product of two primes.

It is not a de Polignac number, because 30101113426555 - 25 = 30101113426523 is a prime.

It is a Duffinian number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3010111342651 + ... + 3010111342660.

It is an arithmetic number, because the mean of its divisors is an integer number (9030334027968).

Almost surely, 230101113426555 is an apocalyptic number.

30101113426555 is a deficient number, since it is larger than the sum of its proper divisors (6020222685317).

30101113426555 is an equidigital number, since it uses as much as digits as its factorization.

30101113426555 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 6020222685316.

The product of its (nonzero) digits is 54000, while the sum is 37.

Adding to 30101113426555 its reverse (55562431110103), we get a palindrome (85663544536658).

The spelling of 30101113426555 in words is "thirty trillion, one hundred one billion, one hundred thirteen million, four hundred twenty-six thousand, five hundred fifty-five".

Divisors: 1 5 6020222685311 30101113426555