Base | Representation |
---|---|
bin | 101011110011011001110… |
… | …010100010101000010001 |
3 | 101122202200012120000101222 |
4 | 223303121302202220101 |
5 | 343304222014341423 |
6 | 10222500214134425 |
7 | 430321565303411 |
oct | 53633162425021 |
9 | 11582605500358 |
10 | 3010131012113 |
11 | a60653534065 |
12 | 407472951415 |
13 | 18ab146cb724 |
14 | a5996600641 |
15 | 53478d803c8 |
hex | 2bcd9ca2a11 |
3010131012113 has 4 divisors (see below), whose sum is σ = 3055058340720. Its totient is φ = 2965203683508.
The previous prime is 3010131012079. The next prime is 3010131012221. The reversal of 3010131012113 is 3112101310103.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 3010131012113 - 216 = 3010130946577 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 3010131012091 and 3010131012100.
It is not an unprimeable number, because it can be changed into a prime (3010131011113) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 22463664203 + ... + 22463664336.
It is an arithmetic number, because the mean of its divisors is an integer number (763764585180).
Almost surely, 23010131012113 is an apocalyptic number.
It is an amenable number.
3010131012113 is a deficient number, since it is larger than the sum of its proper divisors (44927328607).
3010131012113 is an equidigital number, since it uses as much as digits as its factorization.
3010131012113 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 44927328606.
The product of its (nonzero) digits is 54, while the sum is 17.
Adding to 3010131012113 its reverse (3112101310103), we get a palindrome (6122232322216).
The spelling of 3010131012113 in words is "three trillion, ten billion, one hundred thirty-one million, twelve thousand, one hundred thirteen".
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