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30104402153 = 74300628879
BaseRepresentation
bin11100000010010111…
…001011100011101001
32212201000202002012112
4130002113023203221
5443123211332103
621455121452105
72114005124210
oct340227134351
985630662175
1030104402153
1111849171a01
125a01aa1035
132ab9bba517
141658264077
15bb2d9ccd8
hex7025cb8e9

30104402153 has 4 divisors (see below), whose sum is σ = 34405031040. Its totient is φ = 25803773268.

The previous prime is 30104402113. The next prime is 30104402177. The reversal of 30104402153 is 35120440103.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is not a de Polignac number, because 30104402153 - 26 = 30104402089 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (30104402113) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2150314433 + ... + 2150314446.

It is an arithmetic number, because the mean of its divisors is an integer number (8601257760).

Almost surely, 230104402153 is an apocalyptic number.

It is an amenable number.

30104402153 is a deficient number, since it is larger than the sum of its proper divisors (4300628887).

30104402153 is an equidigital number, since it uses as much as digits as its factorization.

30104402153 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 4300628886.

The product of its (nonzero) digits is 1440, while the sum is 23.

Adding to 30104402153 its reverse (35120440103), we get a palindrome (65224842256).

The spelling of 30104402153 in words is "thirty billion, one hundred four million, four hundred two thousand, one hundred fifty-three".

Divisors: 1 7 4300628879 30104402153