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30120022113 = 310040007371
BaseRepresentation
bin11100000011010010…
…110001000001100001
32212202010010122202120
4130003102301001201
5443141211201423
621500440334453
72114254651356
oct340322610141
985663118676
1030120022113
1111856a70465
125a07174429
132ac01c90bc
14165a36c62d
15bb4435ee3
hex7034b1061

30120022113 has 4 divisors (see below), whose sum is σ = 40160029488. Its totient is φ = 20080014740.

The previous prime is 30120022111. The next prime is 30120022129. The reversal of 30120022113 is 31122002103.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 30120022113 - 21 = 30120022111 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 30120022092 and 30120022101.

It is not an unprimeable number, because it can be changed into a prime (30120022111) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5020003683 + ... + 5020003688.

It is an arithmetic number, because the mean of its divisors is an integer number (10040007372).

Almost surely, 230120022113 is an apocalyptic number.

It is an amenable number.

30120022113 is a deficient number, since it is larger than the sum of its proper divisors (10040007375).

30120022113 is a wasteful number, since it uses less digits than its factorization.

30120022113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 10040007374.

The product of its (nonzero) digits is 72, while the sum is 15.

Adding to 30120022113 its reverse (31122002103), we get a palindrome (61242024216).

The spelling of 30120022113 in words is "thirty billion, one hundred twenty million, twenty-two thousand, one hundred thirteen".

Divisors: 1 3 10040007371 30120022113