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30120433 = 74302919
BaseRepresentation
bin111001011100…
…1100111110001
32002200021110121
41302321213301
530202323213
62553330241
7514006450
oct162714761
962607417
1030120433
1116002a22
12a106981
136317a55
144000b97
15299e88d
hex1cb99f1

30120433 has 4 divisors (see below), whose sum is σ = 34423360. Its totient is φ = 25817508.

The previous prime is 30120427. The next prime is 30120439. The reversal of 30120433 is 33402103.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is an interprime number because it is at equal distance from previous prime (30120427) and next prime (30120439).

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-30120433 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (30120439) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2151453 + ... + 2151466.

It is an arithmetic number, because the mean of its divisors is an integer number (8605840).

Almost surely, 230120433 is an apocalyptic number.

It is an amenable number.

30120433 is a deficient number, since it is larger than the sum of its proper divisors (4302927).

30120433 is an equidigital number, since it uses as much as digits as its factorization.

30120433 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 4302926.

The product of its (nonzero) digits is 216, while the sum is 16.

The square root of 30120433 is about 5488.2085419561. The cubic root of 30120433 is about 311.1384880340.

Adding to 30120433 its reverse (33402103), we get a palindrome (63522536).

The spelling of 30120433 in words is "thirty million, one hundred twenty thousand, four hundred thirty-three".

Divisors: 1 7 4302919 30120433