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3012103113 = 36491154681
BaseRepresentation
bin1011001110001001…
…0000101111001001
321202220210200200120
42303202100233021
522132044244423
61214515453453
7134433311505
oct26342205711
97686720616
103012103113
111306287718
127008b7289
13390061446
14208077305
15129684ee3
hexb3890bc9

3012103113 has 8 divisors (see below), whose sum is σ = 4016782176. Its totient is φ = 2007746400.

The previous prime is 3012103111. The next prime is 3012103123. The reversal of 3012103113 is 3113012103.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 3012103113 - 21 = 3012103111 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 3012103092 and 3012103101.

It is not an unprimeable number, because it can be changed into a prime (3012103111) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 57868 + ... + 96813.

It is an arithmetic number, because the mean of its divisors is an integer number (502097772).

Almost surely, 23012103113 is an apocalyptic number.

It is an amenable number.

3012103113 is a deficient number, since it is larger than the sum of its proper divisors (1004679063).

3012103113 is a wasteful number, since it uses less digits than its factorization.

3012103113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 161175.

The product of its (nonzero) digits is 54, while the sum is 15.

The square root of 3012103113 is about 54882.6303396621. The cubic root of 3012103113 is about 1444.1864911659.

Adding to 3012103113 its reverse (3113012103), we get a palindrome (6125115216).

The spelling of 3012103113 in words is "three billion, twelve million, one hundred three thousand, one hundred thirteen".

Divisors: 1 3 6491 19473 154681 464043 1004034371 3012103113