30140100433 has 4 divisors (see below), whose sum is σ = 30954697780. Its totient is φ = 29325503088.

The previous prime is 30140100317. The next prime is 30140100457. The reversal of 30140100433 is 33400104103.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 33400104103 = 31 ⋅1077422713.

It can be written as a sum of positive squares in 2 ways, for example, as 13809305169 + 16330795264 = 117513^2 + 127792^2 .

It is a cyclic number.

It is not a de Polignac number, because 30140100433 - 2¹⁷ = 30139969361 is a prime.

It is a super-2 number, since 2×30140100433² (a number of 22 digits) contains 22 as substring.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 30140100433.

It is not an unprimeable number, because it can be changed into a prime (30140106433) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 407298618 + ... + 407298691.

It is an arithmetic number, because the mean of its divisors is an integer number (7738674445).

Almost surely, 2^30140100433 is an apocalyptic number.

It is an amenable number.

30140100433 is a deficient number, since it is larger than the sum of its proper divisors (814597347).

30140100433 is an equidigital number, since it uses as much as digits as its factorization.

30140100433 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 814597346.

The product of its (nonzero) digits is 432, while the sum is 19.

Adding to 30140100433 its reverse (33400104103), we get a palindrome (63540204536).

The spelling of 30140100433 in words is "thirty billion, one hundred forty million, one hundred thousand, four hundred thirty-three".