Base | Representation |
---|---|
bin | 1101101110100011011001… |
… | …00000001101000111100011 |
3 | 10221212211112111221120010202 |
4 | 12313101230200031013203 |
5 | 12424040132214203310 |
6 | 144111351522415415 |
7 | 6233633203636166 |
oct | 667215440150743 |
9 | 127784474846122 |
10 | 30186850537955 |
11 | 9689198182851 |
12 | 34764b720156b |
13 | 13ac7b9418647 |
14 | 7650a0d17add |
15 | 375368b263a5 |
hex | 1b746c80d1e3 |
30186850537955 has 4 divisors (see below), whose sum is σ = 36224220645552. Its totient is φ = 24149480430360.
The previous prime is 30186850537931. The next prime is 30186850537999. The reversal of 30186850537955 is 55973505868103.
It is a semiprime because it is the product of two primes.
It is not a de Polignac number, because 30186850537955 - 214 = 30186850521571 is a prime.
It is a super-2 number, since 2×301868505379552 (a number of 28 digits) contains 22 as substring.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 30186850537891 and 30186850537900.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3018685053791 + ... + 3018685053800.
It is an arithmetic number, because the mean of its divisors is an integer number (9056055161388).
Almost surely, 230186850537955 is an apocalyptic number.
30186850537955 is a deficient number, since it is larger than the sum of its proper divisors (6037370107597).
30186850537955 is an equidigital number, since it uses as much as digits as its factorization.
30186850537955 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 6037370107596.
The product of its (nonzero) digits is 136080000, while the sum is 65.
The spelling of 30186850537955 in words is "thirty trillion, one hundred eighty-six billion, eight hundred fifty million, five hundred thirty-seven thousand, nine hundred fifty-five".
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