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3021133102001 = 7431590443143
BaseRepresentation
bin101011111101101001100…
…100001011101110110001
3101200211001221221002102122
4223331221210023232301
5343444240033231001
610231520035124025
7431161331442260
oct53755144135661
911624057832378
103021133102001
11a6528996a033
12409623443615
1318bb78ba83a1
14a631b8965d7
15538bebd3b1b
hex2bf6990bbb1

3021133102001 has 4 divisors (see below), whose sum is σ = 3452723545152. Its totient is φ = 2589542658852.

The previous prime is 3021133101991. The next prime is 3021133102073. The reversal of 3021133102001 is 1002013311203.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-3021133102001 is a prime.

It is not an unprimeable number, because it can be changed into a prime (3021133102501) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 215795221565 + ... + 215795221578.

It is an arithmetic number, because the mean of its divisors is an integer number (863180886288).

Almost surely, 23021133102001 is an apocalyptic number.

It is an amenable number.

3021133102001 is a deficient number, since it is larger than the sum of its proper divisors (431590443151).

3021133102001 is an equidigital number, since it uses as much as digits as its factorization.

3021133102001 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 431590443150.

The product of its (nonzero) digits is 108, while the sum is 17.

Adding to 3021133102001 its reverse (1002013311203), we get a palindrome (4023146413204).

The spelling of 3021133102001 in words is "three trillion, twenty-one billion, one hundred thirty-three million, one hundred two thousand, one".

Divisors: 1 7 431590443143 3021133102001