Base | Representation |
---|---|
bin | 101011111111011111100… |
… | …101101010010101101011 |
3 | 101201000011221211112121201 |
4 | 223333133211222111223 |
5 | 344012313434413003 |
6 | 10232444331345031 |
7 | 431261364136540 |
oct | 53773745522553 |
9 | 11630157745551 |
10 | 3023113201003 |
11 | a66105653795 |
12 | 409a965b2177 |
13 | 18c1031a53bc |
14 | a6468850bc7 |
15 | 53988964b1d |
hex | 2bfdf96a56b |
3023113201003 has 4 divisors (see below), whose sum is σ = 3454986515440. Its totient is φ = 2591239886568.
The previous prime is 3023113200959. The next prime is 3023113201007. The reversal of 3023113201003 is 3001023113203.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 3023113201003 - 225 = 3023079646571 is a prime.
It is a super-4 number, since 4×30231132010034 (a number of 51 digits) contains 4444 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (3023113201007) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 215936657208 + ... + 215936657221.
It is an arithmetic number, because the mean of its divisors is an integer number (863746628860).
Almost surely, 23023113201003 is an apocalyptic number.
3023113201003 is a deficient number, since it is larger than the sum of its proper divisors (431873314437).
3023113201003 is an equidigital number, since it uses as much as digits as its factorization.
3023113201003 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 431873314436.
The product of its (nonzero) digits is 324, while the sum is 19.
Adding to 3023113201003 its reverse (3001023113203), we get a palindrome (6024136314206).
The spelling of 3023113201003 in words is "three trillion, twenty-three billion, one hundred thirteen million, two hundred one thousand, three".
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