Base | Representation |
---|---|
bin | 11100001011010111… |
… | …100111101101110001 |
3 | 2220002120002021112120 |
4 | 130023113213231301 |
5 | 443430402344213 |
6 | 21522120344453 |
7 | 2120521420026 |
oct | 341327475561 |
9 | 86076067476 |
10 | 30255512433 |
11 | 119164a2333 |
12 | 5a44615129 |
13 | 2b122b78a3 |
14 | 167035b54d |
15 | bc129b423 |
hex | 70b5e7b71 |
30255512433 has 4 divisors (see below), whose sum is σ = 40340683248. Its totient is φ = 20170341620.
The previous prime is 30255512431. The next prime is 30255512447. The reversal of 30255512433 is 33421555203.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 30255512433 - 21 = 30255512431 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 30255512394 and 30255512403.
It is not an unprimeable number, because it can be changed into a prime (30255512431) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5042585403 + ... + 5042585408.
It is an arithmetic number, because the mean of its divisors is an integer number (10085170812).
Almost surely, 230255512433 is an apocalyptic number.
It is an amenable number.
30255512433 is a deficient number, since it is larger than the sum of its proper divisors (10085170815).
30255512433 is a wasteful number, since it uses less digits than its factorization.
30255512433 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 10085170814.
The product of its (nonzero) digits is 54000, while the sum is 33.
The spelling of 30255512433 in words is "thirty billion, two hundred fifty-five million, five hundred twelve thousand, four hundred thirty-three".
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