Base | Representation |
---|---|
bin | 100010100100101001011110… |
… | …0011001000100001110101001 |
3 | 1110212202001122101020120202020 |
4 | 1011021102330121010032221 |
5 | 304324420020412113023 |
6 | 2554435243245255053 |
7 | 121024535143402422 |
oct | 10511227431041651 |
9 | 1425661571216666 |
10 | 304104025113513 |
11 | 8899587a223589 |
12 | 2a135492864489 |
13 | 1008bb6a8b5451 |
14 | 55149db606649 |
15 | 252569c0d9de3 |
hex | 11494bc6443a9 |
304104025113513 has 4 divisors (see below), whose sum is σ = 405472033484688. Its totient is φ = 202736016742340.
The previous prime is 304104025113461. The next prime is 304104025113569. The reversal of 304104025113513 is 315311520401403.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 304104025113513 - 29 = 304104025113001 is a prime.
It is not an unprimeable number, because it can be changed into a prime (304104025113613) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 50684004185583 + ... + 50684004185588.
It is an arithmetic number, because the mean of its divisors is an integer number (101368008371172).
Almost surely, 2304104025113513 is an apocalyptic number.
It is an amenable number.
304104025113513 is a deficient number, since it is larger than the sum of its proper divisors (101368008371175).
304104025113513 is a wasteful number, since it uses less digits than its factorization.
304104025113513 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 101368008371174.
The product of its (nonzero) digits is 21600, while the sum is 33.
Adding to 304104025113513 its reverse (315311520401403), we get a palindrome (619415545514916).
The spelling of 304104025113513 in words is "three hundred four trillion, one hundred four billion, twenty-five million, one hundred thirteen thousand, five hundred thirteen".
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