Base | Representation |
---|---|
bin | 101100011001100000010… |
… | …111000011001000100001 |
3 | 101210200021110111102212020 |
4 | 230121200113003020201 |
5 | 344442014104410131 |
6 | 10253344025252053 |
7 | 433300462203360 |
oct | 54314027031041 |
9 | 11720243442766 |
10 | 3051043435041 |
11 | a76a38529a38 |
12 | 413390334029 |
13 | 191934806cc4 |
14 | a795803d7d7 |
15 | 545709e9996 |
hex | 2c6605c3221 |
3051043435041 has 8 divisors (see below), whose sum is σ = 4649209043904. Its totient is φ = 1743453391440.
The previous prime is 3051043434899. The next prime is 3051043435043. The reversal of 3051043435041 is 1405343401503.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 3051043435041 - 219 = 3051042910753 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 3051043434993 and 3051043435011.
It is not an unprimeable number, because it can be changed into a prime (3051043435043) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 72643891290 + ... + 72643891331.
It is an arithmetic number, because the mean of its divisors is an integer number (581151130488).
Almost surely, 23051043435041 is an apocalyptic number.
It is an amenable number.
3051043435041 is a deficient number, since it is larger than the sum of its proper divisors (1598165608863).
3051043435041 is a wasteful number, since it uses less digits than its factorization.
3051043435041 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 145287782631.
The product of its (nonzero) digits is 43200, while the sum is 33.
Adding to 3051043435041 its reverse (1405343401503), we get a palindrome (4456386836544).
The spelling of 3051043435041 in words is "three trillion, fifty-one billion, forty-three million, four hundred thirty-five thousand, forty-one".
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