Base | Representation |
---|---|
bin | 101100011010000101010… |
… | …111111001110101111001 |
3 | 101210201212201222112202111 |
4 | 230122011113321311321 |
5 | 344444302042303441 |
6 | 10253525411132321 |
7 | 433322042356006 |
oct | 54320527716571 |
9 | 11721781875674 |
10 | 3051664416121 |
11 | a77227008242 |
12 | 4135242a40a1 |
13 | 191a0336a729 |
14 | a79b66c88ad |
15 | 545aa2ae081 |
hex | 2c6855f9d79 |
3051664416121 has 4 divisors (see below), whose sum is σ = 3052218564432. Its totient is φ = 3051110267812.
The previous prime is 3051664416107. The next prime is 3051664416139. The reversal of 3051664416121 is 1216144661503.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 3051664416121 - 217 = 3051664285049 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (3051664414121) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 277065895 + ... + 277076908.
It is an arithmetic number, because the mean of its divisors is an integer number (763054641108).
Almost surely, 23051664416121 is an apocalyptic number.
It is an amenable number.
3051664416121 is a deficient number, since it is larger than the sum of its proper divisors (554148311).
3051664416121 is an equidigital number, since it uses as much as digits as its factorization.
3051664416121 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 554148310.
The product of its (nonzero) digits is 103680, while the sum is 40.
The spelling of 3051664416121 in words is "three trillion, fifty-one billion, six hundred sixty-four million, four hundred sixteen thousand, one hundred twenty-one".
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