Base | Representation |
---|---|
bin | 1101111000010000001011… |
… | …01111110011010101110001 |
3 | 11000001200210121121210022011 |
4 | 12330020011233303111301 |
5 | 13000020213302210023 |
6 | 144524431144242521 |
7 | 6300002241545632 |
oct | 674100557632561 |
9 | 130050717553264 |
10 | 30520134022513 |
11 | 97a7574aa7683 |
12 | 350b00b170441 |
13 | 140506195b2c5 |
14 | 77727a5c1889 |
15 | 37dd732ed50d |
hex | 1bc205bf3571 |
30520134022513 has 4 divisors (see below), whose sum is σ = 30520614967920. Its totient is φ = 30519653077108.
The previous prime is 30520134022439. The next prime is 30520134022519. The reversal of 30520134022513 is 31522043102503.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-30520134022513 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (30520134022519) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 240377503 + ... + 240504436.
It is an arithmetic number, because the mean of its divisors is an integer number (7630153741980).
Almost surely, 230520134022513 is an apocalyptic number.
It is an amenable number.
30520134022513 is a deficient number, since it is larger than the sum of its proper divisors (480945407).
30520134022513 is an equidigital number, since it uses as much as digits as its factorization.
30520134022513 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 480945406.
The product of its (nonzero) digits is 21600, while the sum is 31.
The spelling of 30520134022513 in words is "thirty trillion, five hundred twenty billion, one hundred thirty-four million, twenty-two thousand, five hundred thirteen".
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