Base | Representation |
---|---|
bin | 101100011011110001000… |
… | …111011010110110111011 |
3 | 101210220112201100001122112 |
4 | 230123301013122312323 |
5 | 400012002320043420 |
6 | 10254425022442535 |
7 | 433414612022450 |
oct | 54336107326673 |
9 | 11726481301575 |
10 | 3053472034235 |
11 | a77a743a5507 |
12 | 41394973344b |
13 | 191c309c714c |
14 | a7b087c5827 |
15 | 54663d1e8c5 |
hex | 2c6f11dadbb |
3053472034235 has 16 divisors (see below), whose sum is σ = 4192012979136. Its totient is φ = 2091612300288.
The previous prime is 3053472034211. The next prime is 3053472034241. The reversal of 3053472034235 is 5324302743503.
It is not a de Polignac number, because 3053472034235 - 210 = 3053472033211 is a prime.
It is a super-3 number, since 3×30534720342353 (a number of 38 digits) contains 333 as substring.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 3053472034192 and 3053472034201.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 45738974 + ... + 45805683.
It is an arithmetic number, because the mean of its divisors is an integer number (262000811196).
Almost surely, 23053472034235 is an apocalyptic number.
3053472034235 is a gapful number since it is divisible by the number (35) formed by its first and last digit.
3053472034235 is a deficient number, since it is larger than the sum of its proper divisors (1138540944901).
3053472034235 is an equidigital number, since it uses as much as digits as its factorization.
3053472034235 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 91545622.
The product of its (nonzero) digits is 907200, while the sum is 41.
Adding to 3053472034235 its reverse (5324302743503), we get a palindrome (8377774777738).
The spelling of 3053472034235 in words is "three trillion, fifty-three billion, four hundred seventy-two million, thirty-four thousand, two hundred thirty-five".
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