Base | Representation |
---|---|
bin | 111010010000… |
… | …0000101010001 |
3 | 2010110121011022 |
4 | 1310200011101 |
5 | 30304240423 |
6 | 3010325225 |
7 | 520405142 |
oct | 164400521 |
9 | 63417138 |
10 | 30540113 |
11 | 1626a26a |
12 | a289815 |
13 | 6433a96 |
14 | 40adac9 |
15 | 2a33dc8 |
hex | 1d20151 |
30540113 has 4 divisors (see below), whose sum is σ = 31867968. Its totient is φ = 29212260.
The previous prime is 30540101. The next prime is 30540119. The reversal of 30540113 is 31104503.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 31104503 = 683 ⋅45541.
It is a cyclic number.
It is not a de Polignac number, because 30540113 - 28 = 30539857 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 30540091 and 30540100.
It is not an unprimeable number, because it can be changed into a prime (30540119) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 663893 + ... + 663938.
It is an arithmetic number, because the mean of its divisors is an integer number (7966992).
Almost surely, 230540113 is an apocalyptic number.
It is an amenable number.
30540113 is a deficient number, since it is larger than the sum of its proper divisors (1327855).
30540113 is a wasteful number, since it uses less digits than its factorization.
30540113 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1327854.
The product of its (nonzero) digits is 180, while the sum is 17.
The square root of 30540113 is about 5526.3109756871. The cubic root of 30540113 is about 312.5769001148.
Adding to 30540113 its reverse (31104503), we get a palindrome (61644616).
The spelling of 30540113 in words is "thirty million, five hundred forty thousand, one hundred thirteen".
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