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30545114433 = 3157251258373
BaseRepresentation
bin11100011100101000…
…010111010101000001
32220211202000120210120
4130130220113111001
51000024022130213
622010543450453
72130636121521
oct343450272501
986752016716
1030545114433
1111a54a14629
125b055b6a29
132b5a2b4912
14169a9c5681
15bdb904423
hex71ca17541

30545114433 has 16 divisors (see below), whose sum is σ = 41149676736. Its totient is φ = 20153016000.

The previous prime is 30545114321. The next prime is 30545114447. The reversal of 30545114433 is 33441154503.

It is not a de Polignac number, because 30545114433 - 232 = 26250147137 is a prime.

It is a super-2 number, since 2×305451144332 (a number of 22 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 30545114394 and 30545114403.

It is not an unprimeable number, because it can be changed into a prime (30545114473) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 10966 + ... + 247407.

It is an arithmetic number, because the mean of its divisors is an integer number (2571854796).

Almost surely, 230545114433 is an apocalyptic number.

It is an amenable number.

30545114433 is a deficient number, since it is larger than the sum of its proper divisors (10604562303).

30545114433 is a wasteful number, since it uses less digits than its factorization.

30545114433 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 258784.

The product of its (nonzero) digits is 43200, while the sum is 33.

Adding to 30545114433 its reverse (33441154503), we get a palindrome (63986268936).

The spelling of 30545114433 in words is "thirty billion, five hundred forty-five million, one hundred fourteen thousand, four hundred thirty-three".

Divisors: 1 3 157 251 471 753 39407 118221 258373 775119 40564561 64851623 121693683 194554869 10181704811 30545114433