Base | Representation |
---|---|
bin | 11100011100101000… |
… | …010111010101000001 |
3 | 2220211202000120210120 |
4 | 130130220113111001 |
5 | 1000024022130213 |
6 | 22010543450453 |
7 | 2130636121521 |
oct | 343450272501 |
9 | 86752016716 |
10 | 30545114433 |
11 | 11a54a14629 |
12 | 5b055b6a29 |
13 | 2b5a2b4912 |
14 | 169a9c5681 |
15 | bdb904423 |
hex | 71ca17541 |
30545114433 has 16 divisors (see below), whose sum is σ = 41149676736. Its totient is φ = 20153016000.
The previous prime is 30545114321. The next prime is 30545114447. The reversal of 30545114433 is 33441154503.
It is not a de Polignac number, because 30545114433 - 232 = 26250147137 is a prime.
It is a super-2 number, since 2×305451144332 (a number of 22 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 30545114394 and 30545114403.
It is not an unprimeable number, because it can be changed into a prime (30545114473) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 10966 + ... + 247407.
It is an arithmetic number, because the mean of its divisors is an integer number (2571854796).
Almost surely, 230545114433 is an apocalyptic number.
It is an amenable number.
30545114433 is a deficient number, since it is larger than the sum of its proper divisors (10604562303).
30545114433 is a wasteful number, since it uses less digits than its factorization.
30545114433 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 258784.
The product of its (nonzero) digits is 43200, while the sum is 33.
Adding to 30545114433 its reverse (33441154503), we get a palindrome (63986268936).
The spelling of 30545114433 in words is "thirty billion, five hundred forty-five million, one hundred fourteen thousand, four hundred thirty-three".
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