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3055052364011 = 15120232134861
BaseRepresentation
bin101100011101001111010…
…011111001100011101011
3101211001121212000010112222
4230131033103321203223
5400023221401122021
610255245514424255
7433502021426054
oct54351723714353
911731555003488
103055052364011
11a7870546167a
1241410aa3208b
1319212323391b
14a7c1863972b
15547079356ab
hex2c74f4f98eb

3055052364011 has 4 divisors (see below), whose sum is σ = 3075284499024. Its totient is φ = 3034820229000.

The previous prime is 3055052363983. The next prime is 3055052364017. The reversal of 3055052364011 is 1104632505503.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-3055052364011 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (3055052364017) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 10116067280 + ... + 10116067581.

It is an arithmetic number, because the mean of its divisors is an integer number (768821124756).

Almost surely, 23055052364011 is an apocalyptic number.

3055052364011 is a deficient number, since it is larger than the sum of its proper divisors (20232135013).

3055052364011 is a wasteful number, since it uses less digits than its factorization.

3055052364011 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 20232135012.

The product of its (nonzero) digits is 54000, while the sum is 35.

Adding to 3055052364011 its reverse (1104632505503), we get a palindrome (4159684869514).

The spelling of 3055052364011 in words is "three trillion, fifty-five billion, fifty-two million, three hundred sixty-four thousand, eleven".

Divisors: 1 151 20232134861 3055052364011