Base | Representation |
---|---|
bin | 101101000111000111000… |
… | …100001111111000000011 |
3 | 101222100200002222122012202 |
4 | 231013013010033320003 |
5 | 401242310331400003 |
6 | 10332043034343415 |
7 | 436653111300464 |
oct | 55070704177003 |
9 | 11870602878182 |
10 | 3100011200003 |
11 | a95786561583 |
12 | 42097758ab6b |
13 | 196439761463 |
14 | aa081630d6b |
15 | 55989942088 |
hex | 2d1c710fe03 |
3100011200003 has 4 divisors (see below), whose sum is σ = 3172104483768. Its totient is φ = 3027917916240.
The previous prime is 3100011199993. The next prime is 3100011200023. The reversal of 3100011200003 is 3000021100013.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 3100011200003 - 210 = 3100011198979 is a prime.
It is a super-2 number, since 2×31000112000032 (a number of 26 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (3100011200023) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 36046641818 + ... + 36046641903.
It is an arithmetic number, because the mean of its divisors is an integer number (793026120942).
Almost surely, 23100011200003 is an apocalyptic number.
3100011200003 is a deficient number, since it is larger than the sum of its proper divisors (72093283765).
3100011200003 is an equidigital number, since it uses as much as digits as its factorization.
3100011200003 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 72093283764.
The product of its (nonzero) digits is 18, while the sum is 11.
Adding to 3100011200003 its reverse (3000021100013), we get a palindrome (6100032300016).
The spelling of 3100011200003 in words is "three trillion, one hundred billion, eleven million, two hundred thousand, three".
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