3100112113 has 4 divisors (see below), whose sum is σ = 3542985280. Its totient is φ = 2657238948.

The previous prime is 3100112111. The next prime is 3100112117. The reversal of 3100112113 is 3112110013.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 3112110013 = 23 ⋅135309131.

It is not a de Polignac number, because 3100112113 - 2¹ = 3100112111 is a prime.

It is a super-2 number, since 2×3100112113² = 19221390226338649538, which contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 3100112093 and 3100112102.

It is not an unprimeable number, because it can be changed into a prime (3100112111) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 221436573 + ... + 221436586.

It is an arithmetic number, because the mean of its divisors is an integer number (885746320).

Almost surely, 2^3100112113 is an apocalyptic number.

It is an amenable number.

3100112113 is a deficient number, since it is larger than the sum of its proper divisors (442873167).

3100112113 is an equidigital number, since it uses as much as digits as its factorization.

3100112113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 442873166.

The product of its (nonzero) digits is 18, while the sum is 13.

The square root of 3100112113 is about 55678.6504236588. The cubic root of 3100112113 is about 1458.1173132423.

Adding to 3100112113 its reverse (3112110013), we get a palindrome (6212222126).

The spelling of 3100112113 in words is "three billion, one hundred million, one hundred twelve thousand, one hundred thirteen".