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31001300403 = 380167128903
BaseRepresentation
bin11100110111110100…
…100100110110110011
32222000112102020022020
4130313310210312303
51001442313103103
622124121242523
72145145464003
oct346764446663
988015366266
1031001300403
1112169475927
126012333443
132c00969148
141701414003
15c169b5753
hex737d24db3

31001300403 has 8 divisors (see below), whose sum is σ = 41335903488. Its totient is φ = 20667115464.

The previous prime is 31001300399. The next prime is 31001300413. The reversal of 31001300403 is 30400310013.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 31001300403 - 22 = 31001300399 is a prime.

It is a super-2 number, since 2×310013004032 (a number of 22 digits) contains 22 as substring.

It is not an unprimeable number, because it can be changed into a prime (31001300413) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 176050 + ... + 304952.

It is an arithmetic number, because the mean of its divisors is an integer number (5166987936).

Almost surely, 231001300403 is an apocalyptic number.

31001300403 is a deficient number, since it is larger than the sum of its proper divisors (10334603085).

31001300403 is a wasteful number, since it uses less digits than its factorization.

31001300403 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 209073.

The product of its (nonzero) digits is 108, while the sum is 15.

Adding to 31001300403 its reverse (30400310013), we get a palindrome (61401610416).

The spelling of 31001300403 in words is "thirty-one billion, one million, three hundred thousand, four hundred three".

Divisors: 1 3 80167 128903 240501 386709 10333766801 31001300403