Base | Representation |
---|---|
bin | 11100110111111110… |
… | …111010101011000011 |
3 | 2222000201111221211020 |
4 | 130313332322223003 |
5 | 1001444011324303 |
6 | 22124255320523 |
7 | 2145210514134 |
oct | 346776725303 |
9 | 88021457736 |
10 | 31004011203 |
11 | 1216aa57560 |
12 | 6013220143 |
13 | 2c013a7c79 |
14 | 170191bc8b |
15 | c16d4da53 |
hex | 737fbaac3 |
31004011203 has 8 divisors (see below), whose sum is σ = 45096743616. Its totient is φ = 18790309800.
The previous prime is 31004011177. The next prime is 31004011217. The reversal of 31004011203 is 30211040013.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 31004011203 - 210 = 31004010179 is a prime.
It is a super-2 number, since 2×310040112032 (a number of 22 digits) contains 22 as substring.
It is not an unprimeable number, because it can be changed into a prime (31004011903) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 469757713 + ... + 469757778.
It is an arithmetic number, because the mean of its divisors is an integer number (5637092952).
Almost surely, 231004011203 is an apocalyptic number.
31004011203 is a gapful number since it is divisible by the number (33) formed by its first and last digit.
31004011203 is a deficient number, since it is larger than the sum of its proper divisors (14092732413).
31004011203 is a wasteful number, since it uses less digits than its factorization.
31004011203 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 939515505.
The product of its (nonzero) digits is 72, while the sum is 15.
Adding to 31004011203 its reverse (30211040013), we get a palindrome (61215051216).
The spelling of 31004011203 in words is "thirty-one billion, four million, eleven thousand, two hundred three".
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