Base | Representation |
---|---|
bin | 1110000110010101100100… |
… | …10101111100000100010011 |
3 | 11001202221220200002022120110 |
4 | 13003022302111330010103 |
5 | 13030432311401204120 |
6 | 145535023223012403 |
7 | 6346653442034436 |
oct | 703126225740423 |
9 | 131687820068513 |
10 | 31004066038035 |
11 | 9973829005562 |
12 | 3588966b9a103 |
13 | 143b894c0b84c |
14 | 79286781781d |
15 | 38b7484ac2e0 |
hex | 1c32b257c113 |
31004066038035 has 16 divisors (see below), whose sum is σ = 50816420434080. Its totient is φ = 16132196962560.
The previous prime is 31004066037977. The next prime is 31004066038073. The reversal of 31004066038035 is 53083066040013.
It is not a de Polignac number, because 31004066038035 - 215 = 31004066005267 is a prime.
It is a super-2 number, since 2×310040660380352 (a number of 28 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 31004066037984 and 31004066038002.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 25206557140 + ... + 25206558369.
It is an arithmetic number, because the mean of its divisors is an integer number (3176026277130).
Almost surely, 231004066038035 is an apocalyptic number.
31004066038035 is a deficient number, since it is larger than the sum of its proper divisors (19812354396045).
31004066038035 is a wasteful number, since it uses less digits than its factorization.
31004066038035 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 50413115558.
The product of its (nonzero) digits is 155520, while the sum is 39.
The spelling of 31004066038035 in words is "thirty-one trillion, four billion, sixty-six million, thirty-eight thousand, thirty-five".
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