3100412113 has 4 divisors (see below), whose sum is σ = 3100741540. Its totient is φ = 3100082688.

The previous prime is 3100412093. The next prime is 3100412131. The reversal of 3100412113 is 3112140013.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 287913024 + 2812499089 = 16968^2 + 53033^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-3100412113 is a prime.

It is a super-2 number, since 2×3100412113² = 19225110540874249538, which contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (3100412713) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 150168 + ... + 169561.

It is an arithmetic number, because the mean of its divisors is an integer number (775185385).

Almost surely, 2^3100412113 is an apocalyptic number.

It is an amenable number.

3100412113 is a deficient number, since it is larger than the sum of its proper divisors (329427).

3100412113 is an equidigital number, since it uses as much as digits as its factorization.

3100412113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 329426.

The product of its (nonzero) digits is 72, while the sum is 16.

The square root of 3100412113 is about 55681.3443893015. The cubic root of 3100412113 is about 1458.1643460666.

Adding to 3100412113 its reverse (3112140013), we get a palindrome (6212552126).

The spelling of 3100412113 in words is "three billion, one hundred million, four hundred twelve thousand, one hundred thirteen".