Base | Representation |
---|---|
bin | 11100110111111111… |
… | …110000001100100001 |
3 | 2222000201221002112212 |
4 | 130313333300030201 |
5 | 1001444040333213 |
6 | 22124304131505 |
7 | 2145212416241 |
oct | 346777601441 |
9 | 88021832485 |
10 | 31004230433 |
11 | 12170097240 |
12 | 6013306b95 |
13 | 2c014539a7 |
14 | 1701977b21 |
15 | c16d939a8 |
hex | 737ff0321 |
31004230433 has 16 divisors (see below), whose sum is σ = 34016140032. Its totient is φ = 28024704000.
The previous prime is 31004230423. The next prime is 31004230459. The reversal of 31004230433 is 33403240013.
It is a cyclic number.
It is not a de Polignac number, because 31004230433 - 24 = 31004230417 is a prime.
It is a super-2 number, since 2×310042304332 (a number of 22 digits) contains 22 as substring.
It is a Duffinian number.
It is a Curzon number.
It is a junction number, because it is equal to n+sod(n) for n = 31004230399 and 31004230408.
It is not an unprimeable number, because it can be changed into a prime (31004230423) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 6750968 + ... + 6755558.
It is an arithmetic number, because the mean of its divisors is an integer number (2126008752).
Almost surely, 231004230433 is an apocalyptic number.
It is an amenable number.
31004230433 is a deficient number, since it is larger than the sum of its proper divisors (3011909599).
31004230433 is a wasteful number, since it uses less digits than its factorization.
31004230433 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 7976.
The product of its (nonzero) digits is 2592, while the sum is 23.
Adding to 31004230433 its reverse (33403240013), we get a palindrome (64407470446).
The spelling of 31004230433 in words is "thirty-one billion, four million, two hundred thirty thousand, four hundred thirty-three".
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