Base | Representation |
---|---|
bin | 1110000110110110111111… |
… | …00010110011000111100001 |
3 | 11001211200012211000001200011 |
4 | 13003123133202303013201 |
5 | 13031231031042100103 |
6 | 145551151221124521 |
7 | 6351160120246624 |
oct | 703333742630741 |
9 | 131750184001604 |
10 | 31022004253153 |
11 | 99803a3728031 |
12 | 3590332559741 |
13 | 14404933b8914 |
14 | 793689d5ddbb |
15 | 38be4820dd6d |
hex | 1c36df8b31e1 |
31022004253153 has 8 divisors (see below), whose sum is σ = 31530655391040. Its totient is φ = 30513356137680.
The previous prime is 31022004253133. The next prime is 31022004253241. The reversal of 31022004253153 is 35135240022013.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-31022004253153 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (31022004253133) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 30357708 + ... + 31362946.
It is an arithmetic number, because the mean of its divisors is an integer number (3941331923880).
Almost surely, 231022004253153 is an apocalyptic number.
It is an amenable number.
31022004253153 is a deficient number, since it is larger than the sum of its proper divisors (508651137887).
31022004253153 is a wasteful number, since it uses less digits than its factorization.
31022004253153 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1511207.
The product of its (nonzero) digits is 21600, while the sum is 31.
Adding to 31022004253153 its reverse (35135240022013), we get a palindrome (66157244275166).
The spelling of 31022004253153 in words is "thirty-one trillion, twenty-two billion, four million, two hundred fifty-three thousand, one hundred fifty-three".
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