Base | Representation |
---|---|
bin | 101101001001111111001… |
… | …011110110100000110011 |
3 | 101222122122101111010222111 |
4 | 231021333023312200303 |
5 | 401320122122413021 |
6 | 10333313342350151 |
7 | 440122500335356 |
oct | 55117713664063 |
9 | 11878571433874 |
10 | 3103100201011 |
11 | a97021190778 |
12 | 421499b8b357 |
13 | 19680c707cc5 |
14 | aa2959a429d |
15 | 55abac168e1 |
hex | 2d27f2f6833 |
3103100201011 has 4 divisors (see below), whose sum is σ = 3103153578000. Its totient is φ = 3103046824024.
The previous prime is 3103100200969. The next prime is 3103100201023. The reversal of 3103100201011 is 1101020013013.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 3103100201011 - 215 = 3103100168243 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 3103100200982 and 3103100201000.
It is not an unprimeable number, because it can be changed into a prime (3103100241011) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 26601196 + ... + 26717593.
It is an arithmetic number, because the mean of its divisors is an integer number (775788394500).
Almost surely, 23103100201011 is an apocalyptic number.
3103100201011 is a deficient number, since it is larger than the sum of its proper divisors (53376989).
3103100201011 is an equidigital number, since it uses as much as digits as its factorization.
3103100201011 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 53376988.
The product of its (nonzero) digits is 18, while the sum is 13.
Adding to 3103100201011 its reverse (1101020013013), we get a palindrome (4204120214024).
The spelling of 3103100201011 in words is "three trillion, one hundred three billion, one hundred million, two hundred one thousand, eleven".
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