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31044004113 = 317608705963
BaseRepresentation
bin11100111010010111…
…011110100100010001
32222010111202210210010
4130322113132210101
51002034231112423
622132244425133
72146204452423
oct347227364421
988114683703
1031044004113
1112190592851
1260246a81a9
132c0976b505
141706d6c813
15c1a5ed693
hex73a5de911

31044004113 has 8 divisors (see below), whose sum is σ = 43826829408. Its totient is φ = 19478590784.

The previous prime is 31044004111. The next prime is 31044004141. The reversal of 31044004113 is 31140044013.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 31044004113 - 21 = 31044004111 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 31044004113.

It is not an unprimeable number, because it can be changed into a prime (31044004111) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 304352931 + ... + 304353032.

It is an arithmetic number, because the mean of its divisors is an integer number (5478353676).

Almost surely, 231044004113 is an apocalyptic number.

It is an amenable number.

31044004113 is a deficient number, since it is larger than the sum of its proper divisors (12782825295).

31044004113 is a wasteful number, since it uses less digits than its factorization.

31044004113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 608705983.

The product of its (nonzero) digits is 576, while the sum is 21.

Adding to 31044004113 its reverse (31140044013), we get a palindrome (62184048126).

The spelling of 31044004113 in words is "thirty-one billion, forty-four million, four thousand, one hundred thirteen".

Divisors: 1 3 17 51 608705963 1826117889 10348001371 31044004113