3105015113 has 4 divisors (see below), whose sum is σ = 3105220560. Its totient is φ = 3104809668.

The previous prime is 3105015091. The next prime is 3105015197. The reversal of 3105015113 is 3115105013.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 3115105013 = 113 ⋅27567301.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-3105015113 is a prime.

It is a super-2 number, since 2×3105015113² = 19282237703916805538, which contains 22 as substring.

It is a Duffinian number.

It is a Curzon number.

It is not an unprimeable number, because it can be changed into a prime (3105015013) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 78083 + ... + 110936.

It is an arithmetic number, because the mean of its divisors is an integer number (776305140).

Almost surely, 2^3105015113 is an apocalyptic number.

It is an amenable number.

3105015113 is a deficient number, since it is larger than the sum of its proper divisors (205447).

3105015113 is a wasteful number, since it uses less digits than its factorization.

3105015113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 205446.

The product of its (nonzero) digits is 225, while the sum is 20.

The square root of 3105015113 is about 55722.6624722832. The cubic root of 3105015113 is about 1458.8856062705.

The spelling of 3105015113 in words is "three billion, one hundred five million, fifteen thousand, one hundred thirteen".