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31100102113 = 383105177261
BaseRepresentation
bin11100111101101101…
…011110010111100001
32222021102022212202211
4130331231132113201
51002143111231423
622142011042121
72150455335433
oct347555362741
988242285684
1031100102113
111220a219033
12603b440341
132c182803b2
1417105b2653
15c204d010d
hex73db5e5e1

31100102113 has 8 divisors (see below), whose sum is σ = 31211375616. Its totient is φ = 30988986000.

The previous prime is 31100102083. The next prime is 31100102153. The reversal of 31100102113 is 31120100113.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 31100102113 - 25 = 31100102081 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 31100102093 and 31100102102.

It is not an unprimeable number, because it can be changed into a prime (31100102153) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 363903 + ... + 441163.

It is an arithmetic number, because the mean of its divisors is an integer number (3901421952).

Almost surely, 231100102113 is an apocalyptic number.

It is an amenable number.

31100102113 is a deficient number, since it is larger than the sum of its proper divisors (111273503).

31100102113 is a wasteful number, since it uses less digits than its factorization.

31100102113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 78695.

The product of its (nonzero) digits is 18, while the sum is 13.

Adding to 31100102113 its reverse (31120100113), we get a palindrome (62220202226).

The spelling of 31100102113 in words is "thirty-one billion, one hundred million, one hundred two thousand, one hundred thirteen".

Divisors: 1 383 1051 77261 402533 29590963 81201311 31100102113