311003000313 has 4 divisors (see below), whose sum is σ = 414670667088. Its totient is φ = 207335333540.

The previous prime is 311003000309. The next prime is 311003000377. The reversal of 311003000313 is 313000300113.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 311003000313 - 2² = 311003000309 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 311003000292 and 311003000301.

It is not an unprimeable number, because it can be changed into a prime (311003000393) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 51833833383 + ... + 51833833388.

It is an arithmetic number, because the mean of its divisors is an integer number (103667666772).

Almost surely, 2^311003000313 is an apocalyptic number.

It is an amenable number.

311003000313 is a deficient number, since it is larger than the sum of its proper divisors (103667666775).

311003000313 is a wasteful number, since it uses less digits than its factorization.

311003000313 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 103667666774.

The product of its (nonzero) digits is 81, while the sum is 15.

Adding to 311003000313 its reverse (313000300113), we get a palindrome (624003300426).

The spelling of 311003000313 in words is "three hundred eleven billion, three million, three hundred thirteen", and thus it is an aban number.