31100302011113 has 4 divisors (see below), whose sum is σ = 31145836861008. Its totient is φ = 31054767161220.

The previous prime is 31100302011089. The next prime is 31100302011133. The reversal of 31100302011113 is 31111020300113.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 31100302011113 - 2¹² = 31100302007017 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 31100302011091 and 31100302011100.

It is not an unprimeable number, because it can be changed into a prime (31100302011133) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 22767423923 + ... + 22767425288.

It is an arithmetic number, because the mean of its divisors is an integer number (7786459215252).

Almost surely, 2^{31100302011113} is an apocalyptic number.

It is an amenable number.

31100302011113 is a deficient number, since it is larger than the sum of its proper divisors (45534849895).

31100302011113 is an equidigital number, since it uses as much as digits as its factorization.

31100302011113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 45534849894.

The product of its (nonzero) digits is 54, while the sum is 17.

Adding to 31100302011113 its reverse (31111020300113), we get a palindrome (62211322311226).

The spelling of 31100302011113 in words is "thirty-one trillion, one hundred billion, three hundred two million, eleven thousand, one hundred thirteen".