Base | Representation |
---|---|
bin | 1001000011010011011… |
… | …10000100100001000001 |
3 | 1002201202220200112222100 |
4 | 10201221232010201001 |
5 | 20043422400030423 |
6 | 354513204101013 |
7 | 31320102454521 |
oct | 4415156044101 |
9 | 1081686615870 |
10 | 311011330113 |
11 | 10a998873620 |
12 | 50339094769 |
13 | 234361c2363 |
14 | 110a5721681 |
15 | 815423a343 |
hex | 4869b84841 |
311011330113 has 12 divisors (see below), whose sum is σ = 490078459728. Its totient is φ = 188491715160.
The previous prime is 311011330111. The next prime is 311011330127. The reversal of 311011330113 is 311033110113.
311011330113 is a `hidden beast` number, since 311 + 0 + 11 + 330 + 1 + 13 = 666.
It is not a de Polignac number, because 311011330113 - 21 = 311011330111 is a prime.
It is not an unprimeable number, because it can be changed into a prime (311011330111) by changing a digit.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 1570764195 + ... + 1570764392.
It is an arithmetic number, because the mean of its divisors is an integer number (40839871644).
Almost surely, 2311011330113 is an apocalyptic number.
311011330113 is a gapful number since it is divisible by the number (33) formed by its first and last digit.
It is an amenable number.
311011330113 is a deficient number, since it is larger than the sum of its proper divisors (179067129615).
311011330113 is a wasteful number, since it uses less digits than its factorization.
311011330113 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 3141528604 (or 3141528601 counting only the distinct ones).
The product of its (nonzero) digits is 81, while the sum is 18.
Adding to 311011330113 its reverse (311033110113), we get a palindrome (622044440226).
The spelling of 311011330113 in words is "three hundred eleven billion, eleven million, three hundred thirty thousand, one hundred thirteen".
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