Base | Representation |
---|---|
bin | 101101010000100001110… |
… | …001101101000101000011 |
3 | 102000022202211010022021121 |
4 | 231100201301231011003 |
5 | 401424012442001011 |
6 | 10340434253333111 |
7 | 440461514212360 |
oct | 55204161550503 |
9 | 12008684108247 |
10 | 3110123000131 |
11 | a99aa5397694 |
12 | 422919a97197 |
13 | 19738b664444 |
14 | aa760577467 |
15 | 55d7c535e71 |
hex | 2d421c6d143 |
3110123000131 has 16 divisors (see below), whose sum is σ = 3596482568448. Its totient is φ = 2634378444000.
The previous prime is 3110123000081. The next prime is 3110123000167. The reversal of 3110123000131 is 1310003210113.
It is a cyclic number.
It is not a de Polignac number, because 3110123000131 - 27 = 3110123000003 is a prime.
It is a super-2 number, since 2×31101230001312 (a number of 26 digits) contains 22 as substring.
It is not an unprimeable number, because it can be changed into a prime (3120123000131) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 3835825 + ... + 4575346.
It is an arithmetic number, because the mean of its divisors is an integer number (224780160528).
Almost surely, 23110123000131 is an apocalyptic number.
3110123000131 is a deficient number, since it is larger than the sum of its proper divisors (486359568317).
3110123000131 is a wasteful number, since it uses less digits than its factorization.
3110123000131 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 8411802.
The product of its (nonzero) digits is 54, while the sum is 16.
Adding to 3110123000131 its reverse (1310003210113), we get a palindrome (4420126210244).
The spelling of 3110123000131 in words is "three trillion, one hundred ten billion, one hundred twenty-three million, one hundred thirty-one", and thus it is an aban number.
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