311013111331 has 4 divisors (see below), whose sum is σ = 334937196832. Its totient is φ = 287089025832.

The previous prime is 311013111313. The next prime is 311013111359. The reversal of 311013111331 is 133111310113.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 133111310113 = 19 ⋅7005858427.

It is a cyclic number.

It is not a de Polignac number, because 311013111331 - 2¹³ = 311013103139 is a prime.

It is a super-2 number, since 2×311013111331² (a number of 24 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 311013111299 and 311013111308.

It is not an unprimeable number, because it can be changed into a prime (311013111931) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 11962042731 + ... + 11962042756.

It is an arithmetic number, because the mean of its divisors is an integer number (83734299208).

Almost surely, 2^311013111331 is an apocalyptic number.

311013111331 is a deficient number, since it is larger than the sum of its proper divisors (23924085501).

311013111331 is a wasteful number, since it uses less digits than its factorization.

311013111331 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 23924085500.

The product of its (nonzero) digits is 81, while the sum is 19.

Adding to 311013111331 its reverse (133111310113), we get a palindrome (444124421444).

The spelling of 311013111331 in words is "three hundred eleven billion, thirteen million, one hundred eleven thousand, three hundred thirty-one".