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31102013011 = 81143278863
BaseRepresentation
bin11100111101110100…
…110000111001010011
32222021112220222000211
4130331310300321103
51002144103404021
622142120024551
72150510514526
oct347564607123
988245828024
1031102013011
1112210303793
126040002157
132c1879c0c4
14171094cbbd
15c2075b3e1
hex73dd30e53

31102013011 has 8 divisors (see below), whose sum is σ = 31151074304. Its totient is φ = 31052979720.

The previous prime is 31102012999. The next prime is 31102013053. The reversal of 31102013011 is 11031020113.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 31102013011 - 211 = 31102010963 is a prime.

It is a super-2 number, since 2×311020130112 (a number of 22 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 31102012982 and 31102013000.

It is not an unprimeable number, because it can be changed into a prime (31102073011) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 3504766 + ... + 3513628.

It is an arithmetic number, because the mean of its divisors is an integer number (3893884288).

Almost surely, 231102013011 is an apocalyptic number.

31102013011 is a deficient number, since it is larger than the sum of its proper divisors (49061293).

31102013011 is an equidigital number, since it uses as much as digits as its factorization.

31102013011 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 14001.

The product of its (nonzero) digits is 18, while the sum is 13.

Adding to 31102013011 its reverse (11031020113), we get a palindrome (42133033124).

The spelling of 31102013011 in words is "thirty-one billion, one hundred two million, thirteen thousand, eleven".

Divisors: 1 811 4327 8863 3509197 7187893 38350201 31102013011