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31102013131 = 74443144733
BaseRepresentation
bin11100111101110100…
…110000111011001011
32222021112220222012021
4130331310300323023
51002144103410011
622142120025311
72150510515060
oct347564607313
988245828167
1031102013131
1112210303892
126040002237
132c1879c187
14171094cc67
15c2075b471
hex73dd30ecb

31102013131 has 4 divisors (see below), whose sum is σ = 35545157872. Its totient is φ = 26658868392.

The previous prime is 31102013099. The next prime is 31102013141. The reversal of 31102013131 is 13131020113.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 13131020113 = 29452793797.

It is a cyclic number.

It is not a de Polignac number, because 31102013131 - 25 = 31102013099 is a prime.

It is a super-2 number, since 2×311020131312 (a number of 22 digits) contains 22 as substring.

It is not an unprimeable number, because it can be changed into a prime (31102013141) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2221572360 + ... + 2221572373.

It is an arithmetic number, because the mean of its divisors is an integer number (8886289468).

Almost surely, 231102013131 is an apocalyptic number.

31102013131 is a deficient number, since it is larger than the sum of its proper divisors (4443144741).

31102013131 is an equidigital number, since it uses as much as digits as its factorization.

31102013131 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 4443144740.

The product of its (nonzero) digits is 54, while the sum is 16.

Adding to 31102013131 its reverse (13131020113), we get a palindrome (44233033244).

The spelling of 31102013131 in words is "thirty-one billion, one hundred two million, thirteen thousand, one hundred thirty-one".

Divisors: 1 7 4443144733 31102013131