Base | Representation |
---|---|
bin | 11100111101110100… |
… | …110000111011001011 |
3 | 2222021112220222012021 |
4 | 130331310300323023 |
5 | 1002144103410011 |
6 | 22142120025311 |
7 | 2150510515060 |
oct | 347564607313 |
9 | 88245828167 |
10 | 31102013131 |
11 | 12210303892 |
12 | 6040002237 |
13 | 2c1879c187 |
14 | 171094cc67 |
15 | c2075b471 |
hex | 73dd30ecb |
31102013131 has 4 divisors (see below), whose sum is σ = 35545157872. Its totient is φ = 26658868392.
The previous prime is 31102013099. The next prime is 31102013141. The reversal of 31102013131 is 13131020113.
It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 13131020113 = 29 ⋅452793797.
It is a cyclic number.
It is not a de Polignac number, because 31102013131 - 25 = 31102013099 is a prime.
It is a super-2 number, since 2×311020131312 (a number of 22 digits) contains 22 as substring.
It is not an unprimeable number, because it can be changed into a prime (31102013141) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2221572360 + ... + 2221572373.
It is an arithmetic number, because the mean of its divisors is an integer number (8886289468).
Almost surely, 231102013131 is an apocalyptic number.
31102013131 is a deficient number, since it is larger than the sum of its proper divisors (4443144741).
31102013131 is an equidigital number, since it uses as much as digits as its factorization.
31102013131 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 4443144740.
The product of its (nonzero) digits is 54, while the sum is 16.
Adding to 31102013131 its reverse (13131020113), we get a palindrome (44233033244).
The spelling of 31102013131 in words is "thirty-one billion, one hundred two million, thirteen thousand, one hundred thirty-one".
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