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311031004021993 = 2313523087131391
BaseRepresentation
bin100011010111000011000110…
…0100000100100010011101001
31111210021021101110010202210101
41012232012030200210103221
5311231412444012200433
63021301400511345401
7122341151141544163
oct10656061440442351
91453237343122711
10311031004021993
1190116565233002
122aa73a85b22261
1310472136c089c8
1456b3da38cd933
1525e596bd6a07d
hex11ae18c8244e9

311031004021993 has 4 divisors (see below), whose sum is σ = 324554091153408. Its totient is φ = 297507916890580.

The previous prime is 311031004021961. The next prime is 311031004021999. The reversal of 311031004021993 is 399120400130113.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 311031004021993 - 25 = 311031004021961 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (311031004021999) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 6761543565673 + ... + 6761543565718.

It is an arithmetic number, because the mean of its divisors is an integer number (81138522788352).

Almost surely, 2311031004021993 is an apocalyptic number.

It is an amenable number.

311031004021993 is a deficient number, since it is larger than the sum of its proper divisors (13523087131415).

311031004021993 is a wasteful number, since it uses less digits than its factorization.

311031004021993 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 13523087131414.

The product of its (nonzero) digits is 17496, while the sum is 37.

The spelling of 311031004021993 in words is "three hundred eleven trillion, thirty-one billion, four million, twenty-one thousand, nine hundred ninety-three".

Divisors: 1 23 13523087131391 311031004021993